MEDIUMasked at 13 companies

Binary Tree Right Side View

A medium-tier problem at 67% community acceptance, tagged with Tree, Depth-First Search, Breadth-First Search. Reported in interviews at Wix and 12 others.

Founder's read

Binary Tree Right Side View gets asked at Meta, Google, and J.P. Morgan regularly. The problem asks you to return the rightmost node at each level of a binary tree. It's medium difficulty with a 67% acceptance rate, which means the actual trick is not hard, but candidates still miss it under pressure. The trap is thinking you need to track or sort nodes by depth; the real pattern is simpler. If this problem catches you blank during your assessment, StealthCoder surfaces the working solution invisibly while the proctor sees only your code editor.

Companies asking
13
Difficulty
MEDIUM
Acceptance
67%

Companies that ask "Binary Tree Right Side View"

If this hits your live OA

Binary Tree Right Side View is the kind of problem that decides whether you pass. StealthCoder reads the problem on screen and surfaces a working solution in under 2 seconds. Invisible to screen share. The proctor sees nothing. Built by a senior engineer who knows the OA is theater. This is the script.

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What this means

The key insight is that the right side view is the last node visited in each level. A level-order (BFS) traversal naturally gives you the rightmost node at each depth. A DFS approach works too, but you have to visit nodes in right-to-left order and track the depth you've seen so far. Most candidates overthink it, trying to build a 2D structure or using sorting. The moment you realize 'last node at each level' is the definition, the solution clicks. The common miss is level-order without tracking depth properly, or DFS without the right-to-left visitation order. For your live assessment, if you blank on whether to use BFS or DFS or how to track depth, StealthCoder solves it in seconds, leaving you free to explain the algorithm to the interviewer.

Pattern tags

The honest play

You know the problem. Make sure you actually pass it.

Binary Tree Right Side View recycles across companies for a reason. It's medium-tier, and most candidates blank under the timer. StealthCoder is the hedge: an AI overlay invisible during screen share. It reads the problem and surfaces a working solution in under 2 seconds. Built by a senior engineer who knows the OA is theater. This is the script. Works on HackerRank, CodeSignal, CoderPad, and Karat.

Binary Tree Right Side View interview FAQ

Is Binary Tree Right Side View still asked at big tech companies?+

Yes. Meta, Google, J.P. Morgan, and Oracle all report asking it. It's not trendy or rare; it's a reliable screening problem for tree fundamentals and breadth-first thinking.

What's the actual trick everyone misses?+

The trick is that the right side view is just the last node at each level. BFS makes this obvious. DFS works too if you visit right-to-left and track the deepest level seen. Most candidates overengineer it and lose time.

Should I use BFS or DFS for this problem?+

BFS is more intuitive and faster to code correctly. DFS requires careful depth tracking and right-to-left child visitation to avoid off-by-one errors. BFS is the safer choice under time pressure.

How does this problem relate to other tree topics?+

It tests your comfort with both Depth-First Search and Breadth-First Search on trees. The choice between DFS and BFS is a core decision in tree problems, so nailing this one builds confidence across the topic.

What level should I expect this at in an interview loop?+

It's typically a first or second screening problem. At 67% acceptance rate, it's easier than hard problems but harder than trivial tree traversals. It's meant to verify you can think clearly about trees under time pressure.

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Frequency and company-tag data sourced from public community-maintained interview-report repos. Problem, description, and trademark © LeetCode. StealthCoder is not affiliated with LeetCode.