HARDasked at 1 company

Minimum Number of Flips to Convert Binary Matrix to Zero Matrix

A hard-tier problem at 72% community acceptance, tagged with Array, Hash Table, Bit Manipulation. Reported in interviews at Airbnb and 0 others.

Founder's read

You've got a matrix of 0s and 1s. Flip a cell, and it flips its neighbors too. Get everything to 0 in minimum moves. This is the kind of problem that looks like brute force on the surface but punishes you hard if you try to simulate every flip. Airbnb asks it. The catch: the state space explodes fast, so most candidates get stuck halfway through coding. If this hits your live OA and you blank on the right encoding, StealthCoder surfaces a working solution invisible to the proctor.

Companies asking
1
Difficulty
HARD
Acceptance
72%

Companies that ask "Minimum Number of Flips to Convert Binary Matrix to Zero Matrix"

If this hits your live OA

Minimum Number of Flips to Convert Binary Matrix to Zero Matrix is the kind of problem that decides whether you pass. StealthCoder reads the problem on screen and surfaces a working solution in under 2 seconds. Invisible to screen share. The proctor sees nothing. Made by a working Amazon engineer who got tired of watching qualified friends bomb OAs they'd solve cold in an IDE.

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What this means

The key insight is that each cell's final state depends on how many times it gets flipped (by itself and its neighbors). Since flipping twice cancels out, each cell is either flipped or not. That's binary. You need to model this as a system of linear equations over GF(2), or use BFS with bitwise state encoding to explore the solution space. Bit manipulation is your friend here: represent the entire matrix as a bitmask, track visited states in a hash table, and BFS from the initial state to zero. The trap: treating it like a greedy grid problem. It's not. You must commit to state-space search. When the obvious cell-by-cell approach stalls, that's your signal the pattern requires a different model entirely.

Pattern tags

The honest play

You know the problem. Make sure you actually pass it.

Minimum Number of Flips to Convert Binary Matrix to Zero Matrix recycles across companies for a reason. It's hard-tier, and most candidates blank under the timer. StealthCoder is the hedge: an AI overlay invisible during screen share. It reads the problem and surfaces a working solution in under 2 seconds. Made by a working Amazon engineer who got tired of watching qualified friends bomb OAs they'd solve cold in an IDE. Works on HackerRank, CodeSignal, CoderPad, and Karat.

Minimum Number of Flips to Convert Binary Matrix to Zero Matrix interview FAQ

Is this really a hard problem or does it just look hard?+

It's genuinely hard. The 0.72 acceptance rate is misleading because it counts all submissions, including those from people who recognize the BFS-with-bitmask pattern. If you don't know that pattern upfront, you'll waste time on simulation or greedy approaches that fail on medium-sized inputs.

How do I know when to use bitmask encoding instead of simulating flips?+

Simulate a few steps manually. If you find yourself tracking state and backtracking, you need a better representation. Bitmask encoding lets you represent the entire matrix as one integer (for small matrices), store visited states, and use BFS. That's your signal.

What's the relationship between Bit Manipulation and Hash Table here?+

Bit manipulation encodes the matrix state compactly. Hash table (or set) stores visited states so you don't revisit them. Together they make BFS feasible. Without the hash table, you'd loop forever. Without bit manipulation, you'd run out of memory.

Does Airbnb always ask the matrix version, or do they vary the input format?+

The core logic is consistent across variants. Airbnb and others test your ability to recognize state-space search and encode state efficiently. The trick translates even if the problem is reworded as a light-switch puzzle or a bit-flip game.

What's the most common mistake on this problem?+

Assuming a greedy or local approach works. Candidates flip the cell that minimizes 1s in the neighborhood, then get stuck on cases where the optimal solution requires flips that temporarily increase 1s. That's when you realize you need full state exploration, not heuristics.

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