Find Minimum in Rotated Sorted Array
A medium-tier problem at 53% community acceptance, tagged with Array, Binary Search. Reported in interviews at Synopsys and 18 others.
Find Minimum in Rotated Sorted Array hits your OA and you panic. A sorted array, rotated at some unknown pivot. Just scan it linearly and find the min, right? Wrong. That's O(n) and the problem demands binary search. Companies like Microsoft, Tesla, Goldman Sachs, and TikTok ask this constantly. The trick is that a rotated sorted array has two sorted halves, and the minimum always sits at the boundary. Miss the pattern and you'll waste ten minutes on a brute force that won't pass. If you blank on the binary search logic mid-assessment, StealthCoder surfaces the solution invisible to the proctor.
Companies that ask "Find Minimum in Rotated Sorted Array"
Find Minimum in Rotated Sorted Array is the kind of problem that decides whether you pass. StealthCoder reads the problem on screen and surfaces a working solution in under 2 seconds. Invisible to screen share. The proctor sees nothing. Made by an Amazon engineer who watched the leaked-problem repo become an industry secret. He decided you should have it too.
Get StealthCoderThe core insight: in a rotated sorted array, one half is always properly sorted. Binary search by comparing the middle element to the right boundary. If mid is greater than right, the minimum is in the right half. If mid is less than right, it's in the left half (or at mid). The trap candidates fall into is confusing this with the standard binary search pattern, or overthinking edge cases like duplicate elements. The acceptance rate hovers at 53 percent, which tells you plenty of candidates miss the boundary logic or implement it carelessly under pressure. This is exactly where StealthCoder hedges your live assessment. You either nail the binary search contraints or you don't, and there's no time to debug on the clock.
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Find Minimum in Rotated Sorted Array recycles across companies for a reason. It's medium-tier, and most candidates blank under the timer. StealthCoder is the hedge: an AI overlay invisible during screen share. It reads the problem and surfaces a working solution in under 2 seconds. Made by an Amazon engineer who watched the leaked-problem repo become an industry secret. He decided you should have it too. Works on HackerRank, CodeSignal, CoderPad, and Karat.
Find Minimum in Rotated Sorted Array interview FAQ
Is this problem still actually asked at big tech companies?+
Yes. Microsoft, Tesla, Goldman Sachs, and TikTok report asking it frequently. It's a screening problem that separates candidates who understand binary search fundamentals from those who don't. The 53 percent acceptance rate shows it's harder than it looks under interview pressure.
What's the trick I'm missing if I keep getting it wrong?+
You're likely comparing mid to the wrong boundary, or not recognizing that one half is always sorted. The key: always compare mid to the right boundary, not left. If mid > right, minimum is right. If mid < right, minimum is left or at mid. That single rule is the entire algorithm.
Can I just do a linear scan instead of binary search?+
Technically yes, but the problem expects O(log n). Linear scan won't pass on large test cases or time limit. Interviewers use this problem to verify you can adapt binary search to a rotated structure. Don't take the shortcut.
How does this relate to the other binary search problems I've drilled?+
Standard binary search finds a target. This problem finds a minimum in a modified structure. The mental shift is recognizing that half of the array always maintains its sorted property, even after rotation. That property is what makes binary search work here instead of linear scan.
What happens if there are duplicate elements?+
Duplicates break the algorithm because you can't reliably determine which half is sorted. Some versions of this problem exclude duplicates. If you hit duplicates during your OA, ask the interviewer for clarification. The core logic stays the same, but edge case handling gets messier.
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