Employee Importance
A medium-tier problem at 68% community acceptance, tagged with Array, Hash Table, Tree. Reported in interviews at Rippling and 1 others.
Employee Importance is a medium-difficulty tree traversal problem that shows up in assessments at Rippling and Robinhood. You're given an employee structure and need to calculate total importance across a hierarchy, usually starting from a specific employee. The trick is recognizing this is a graph traversal problem hiding inside a tree problem, and most people's first instinct (recursive DFS) works fine, but you need to handle the structure correctly. With a 68% acceptance rate, it's passable but enough candidates stumble on implementation or edge cases that it's worth knowing cold. If this one hits your live OA and you blank on the traversal pattern, StealthCoder solves it invisibly in seconds.
Companies that ask "Employee Importance"
Employee Importance is the kind of problem that decides whether you pass. StealthCoder reads the problem on screen and surfaces a working solution in under 2 seconds. Invisible to screen share. The proctor sees nothing. Built by an Amazon engineer who realized the OA tests how well you memorized 200 problems, not how well you code.
Get StealthCoderThe core pattern: you've got an employee object with an ID, importance value, and a list of subordinates (direct reports). You start at one employee and sum up importance across that entire subtree. Candidates usually overcomplicate this by trying to build a separate graph structure when the subordinate list is already your adjacency. The common failures are forgetting to mark visited nodes (creating cycles if the input isn't strictly a tree), or writing messy recursive calls that lose track of the running sum. DFS or BFS both work, but DFS is cleaner. The gotcha isn't algorithmic hardness, it's careful implementation and handling the tree structure as given. Whether you approach this top-down recursion or iterative BFS, the real win is not overthinking the data model. StealthCoder is your hedge if you freeze on whether to use a queue or stack, or if you lose the thread during the live screen share.
Pattern tags
You know the problem.
Make sure you actually pass it.
Employee Importance recycles across companies for a reason. It's medium-tier, and most candidates blank under the timer. StealthCoder is the hedge: an AI overlay invisible during screen share. It reads the problem and surfaces a working solution in under 2 seconds. Built by an Amazon engineer who realized the OA tests how well you memorized 200 problems, not how well you code. Works on HackerRank, CodeSignal, CoderPad, and Karat.
Employee Importance interview FAQ
Is Employee Importance actually a tree problem or a graph problem?+
It's a tree problem dressed as a graph problem. The subordinates list forms a tree rooted at your starting employee. The confusion happens because you might think you need cycle detection, but the input is a valid tree hierarchy. Treat it as pure tree traversal and you'll avoid unnecessary visited-set overhead.
Do I have to use recursion, or is iteration fine?+
Both work. Recursive DFS is shorter and more intuitive for tree traversal, but iterative BFS or DFS with a stack is equally valid and sometimes safer if you're worried about stack overflow on deep trees. Most solutions use recursion, and it passes the acceptance threshold, so pick whichever you're faster in during the live assessment.
What's the trick if I don't know which employee to start from?+
The problem gives you a starting employee ID, so you usually build a hash map of ID to employee object first, then look up your starting point. If the input is an employee graph or list, you might need to search, but that's an O(n) one-time cost. The main traversal is still O(n) regardless.
Why does this problem appear at Rippling and Robinhood?+
Both companies deal with organizational hierarchies and team structures in their product. Rippling is HCM software, Robinhood has internal org charts. This problem tests whether you can model and traverse a real-world structure without overengineering it, which is a practical skill in those domains.
Is 68% acceptance rate high enough that I can skip this problem?+
No. A 68% pass rate means one in three candidates fail. At Rippling or Robinhood especially, this problem is directionally relevant to their business. If you hit it cold in your OA without having drilled tree traversal patterns, you could blank on the implementation. It's worth one solid practice run to build muscle memory.
Want the actual problem statement? View "Employee Importance" on LeetCode →