Divisible and Non-divisible Sums Difference
A easy-tier problem at 91% community acceptance, tagged with Math. Reported in interviews at Amazon and 0 others.
Amazon's asking this one, and it's got a 91% acceptance rate for a reason. The problem looks simple on the surface: take numbers, bucket them by some divisibility rule, sum each bucket, find the difference. The trap is overthinking it. Most candidates burn time building hash maps or nested loops when the math collapses to a single pass. If you hit this live and freeze on the optimal path, StealthCoder surfaces the clean solution in seconds while your proctor sees nothing.
Companies that ask "Divisible and Non-divisible Sums Difference"
Divisible and Non-divisible Sums Difference is the kind of problem that decides whether you pass. StealthCoder reads the problem on screen and surfaces a working solution in under 2 seconds. Invisible to screen share. The proctor sees nothing. Made by an Amazon engineer who watched the leaked-problem repo become an industry secret. He decided you should have it too.
Get StealthCoderThis is a Math problem that rewards pattern recognition over brute force. The divisibility condition is the key. You need to separate your input into two groups based on whether each element satisfies the rule, compute the sums, and return the absolute difference. The naive approach works (iterate, check, accumulate), but the real insight is recognizing that you don't need fancy data structures. One loop, two running sums, done. The acceptance rate stays high because once you see the pattern, there's almost no way to mess it up. The risk is spending interview time on premature optimization or misreading the divisibility constraint. StealthCoder is the hedge if you misunderstand the problem statement or blank on the loop structure under pressure.
Pattern tags
You know the problem.
Make sure you actually pass it.
Divisible and Non-divisible Sums Difference recycles across companies for a reason. It's easy-tier, and most candidates blank under the timer. StealthCoder is the hedge: an AI overlay invisible during screen share. It reads the problem and surfaces a working solution in under 2 seconds. Made by an Amazon engineer who watched the leaked-problem repo become an industry secret. He decided you should have it too. Works on HackerRank, CodeSignal, CoderPad, and Karat.
Divisible and Non-divisible Sums Difference interview FAQ
How hard is 'Divisible and Non-divisible Sums Difference' really?+
The 91% acceptance rate tells you it's legitimately easy. It's a one-pass loop with a conditional sum. No recursion, no tree traversal, no dynamic programming. If you can read the divisibility rule and accumulate two separate totals, you solve it. The difficulty floor is 'can you parse the problem statement.' Most failures are careless reads, not algorithmic gaps.
Why is Amazon asking this on their online assessments?+
Amazon uses easy Math problems as baseline filters. They're not probing for advanced CS knowledge. They're checking if you code cleanly, read carefully, and avoid overthinking. A 91% pass rate means it's a reset problem. You either nail it and build confidence, or you miss something fundamental and they learn something about your attention to detail.
What's the trick to solving this fast?+
There is no trick. Read the divisibility rule twice. Iterate once. Maintain two sums. Return the difference. The speed trap is re-reading the problem mid-code because you doubted yourself. Commit to your interpretation and code it. Verify on the example. Done in under two minutes.
Should I use a hash map or two separate arrays?+
No. You don't need to store anything. You only need the final sums. Iterate once, check the condition, add to sum A or sum B, move on. Any data structure beyond two accumulators is wasted memory and CPU. Keep it linear and obvious.
How does this Math problem relate to other Amazon OA questions?+
It's a warm-up. Amazon's easy tier tests your ability to parse requirements and execute basic logic cleanly. Pass this, and you move to medium problems that layer on complexity. Fail it, and they flag you as someone who rushes or misreads. This problem isn't about being smart. It's about being careful and direct.
Want the actual problem statement? View "Divisible and Non-divisible Sums Difference" on LeetCode →