MEDIUMasked at 3 companies

Divide Players Into Teams of Equal Skill

A medium-tier problem at 69% community acceptance, tagged with Array, Hash Table, Two Pointers. Reported in interviews at Expedia and 2 others.

Founder's read

Divide Players Into Teams of Equal Skill is a medium-difficulty problem that shows up in assessments at Expedia, IBM, and PayPal. You're given a list of player skill levels and need to form pairs where each pair has the same total skill value. The trick isn't the pairing itself, it's figuring out which sorting and matching strategy avoids the O(n²) trap that derails most people on the first attempt. With a 69% acceptance rate, this problem splits candidates cleanly: those who see the pattern solve it in minutes, those who don't spend the whole assessment fighting edge cases. If this problem hits your live OA and you blank on the approach, StealthCoder surfaces a working solution in seconds, invisible to the proctor.

Companies asking
3
Difficulty
MEDIUM
Acceptance
69%

Companies that ask "Divide Players Into Teams of Equal Skill"

If this hits your live OA

Divide Players Into Teams of Equal Skill is the kind of problem that decides whether you pass. StealthCoder reads the problem on screen and surfaces a working solution in under 2 seconds. Invisible to screen share. The proctor sees nothing. Built by a senior engineer who knows the OA is theater. This is the script.

Get StealthCoder
What this means

Sort the array first, then use two pointers to form pairs from the ends. The insight is that after sorting, the smallest and largest skill values must pair together if a valid division exists. Once you've committed to that pairing, the remaining players inherit a constraint: all pairs must have the same sum. This eliminates backtracking and makes validation linear. The common mistake is trying to brute-force assignments with a hash table before sorting, which creates false complexity. Array and Hash Table both matter here, but Two Pointers and Sorting are where the logic lives. StealthCoder serves as the hedge for the one candidate who didn't practice this specific pattern before the assessment, letting you verify your pairing logic is sound and dodge the off-by-one errors that normally surface at runtime.

Pattern tags

The honest play

You know the problem. Make sure you actually pass it.

Divide Players Into Teams of Equal Skill recycles across companies for a reason. It's medium-tier, and most candidates blank under the timer. StealthCoder is the hedge: an AI overlay invisible during screen share. It reads the problem and surfaces a working solution in under 2 seconds. Built by a senior engineer who knows the OA is theater. This is the script. Works on HackerRank, CodeSignal, CoderPad, and Karat.

Divide Players Into Teams of Equal Skill interview FAQ

Is this problem still asked at major tech companies?+

Yes. Expedia, IBM, and PayPal have all reported it. At 69% acceptance, it's popular enough to show up frequently but hard enough that candidates don't always ace it on sight. It's a solid screen filter for mid-level engineers because it separates people who know sorting and two-pointer tricks from those who don't.

What's the actual trick everyone misses?+

Trying to solve it without sorting first. Most candidates jump straight to a hash table or greedy matching, which creates complicated state. Sort once, then pair smallest with largest. If that pairing's sum doesn't match the second-smallest with second-largest, no valid division exists. The sort makes the validation trivial.

How do Array and Hash Table connect here?+

Array handles the sorted iteration and two-pointer traversal. Hash Table isn't mandatory but some solutions use it to count skill occurrences upfront or validate that pairs exist. The cleaner approaches skip the hash table entirely and rely on sorting plus pointer logic, which is why it's not the bottleneck.

What edge cases break common solutions?+

Odd player count (no valid division). Players with identical skill levels (your pointers might skip valid pairings). Not checking that all pairs sum to the same value before returning success. A pass should only happen if every single pair has the same total skill, not just the first one.

How much time should this take in a real assessment?+

If you know the two-pointer pattern, 8 to 12 minutes including write and test. If you're seeing it cold, you'll spend time on false starts with greedy or hash-first approaches. That's why this problem is a good hedge case for StealthCoder on the live OA if the pattern doesn't surface immediately.

Want the actual problem statement? View "Divide Players Into Teams of Equal Skill" on LeetCode →

Frequency and company-tag data sourced from public community-maintained interview-report repos. Problem, description, and trademark © LeetCode. StealthCoder is not affiliated with LeetCode.