Check if Number Has Equal Digit Count and Digit Value
A easy-tier problem at 72% community acceptance, tagged with Hash Table, String, Counting. Reported in interviews at PornHub and 1 others.
You're looking at a problem that sounds trivial on the surface: check if a number's digits match both their count and their value. Easy difficulty, 72% acceptance rate. But that acceptance number hides something. People blank on the constraint parsing. You read "the digit 2 appears exactly 2 times" and your brain goes quiet. This problem appears in PornHub and J.P. Morgan assessments. If it shows up in your live OA and you misread the constraint, StealthCoder surfaces the correct interpretation and a working solution in seconds while the proctor sees nothing.
Companies that ask "Check if Number Has Equal Digit Count and Digit Value"
Check if Number Has Equal Digit Count and Digit Value is the kind of problem that decides whether you pass. StealthCoder reads the problem on screen and surfaces a working solution in under 2 seconds. Invisible to screen share. The proctor sees nothing. Built by an engineer who got tired of watching his cohort grind for six months and still get filtered at the OA stage.
Get StealthCoderThe trick is reading the constraint precisely. You're not just counting digits; you're verifying that the digit n appears exactly n times in the number string. Hash Table is the immediate go-to: count each digit's frequency, then validate the rule for every digit present. Pitfall: candidates overthink it or misinterpret what "digit value" means in context. The obvious brute-force approach works fine here since the input is small, but you still need to handle edge cases like missing digits or the digit 0 appearing 0 times. String conversion and counting are your tools. When you hit this live and panic on the constraint, StealthCoder reads the problem clean and hands you the hash-table validation logic so you don't waste 15 minutes chasing the wrong interpretation.
Pattern tags
You know the problem.
Make sure you actually pass it.
Check if Number Has Equal Digit Count and Digit Value recycles across companies for a reason. It's easy-tier, and most candidates blank under the timer. StealthCoder is the hedge: an AI overlay invisible during screen share. It reads the problem and surfaces a working solution in under 2 seconds. Built by an engineer who got tired of watching his cohort grind for six months and still get filtered at the OA stage. Works on HackerRank, CodeSignal, CoderPad, and Karat.
Check if Number Has Equal Digit Count and Digit Value interview FAQ
What does 'digit value' actually mean in this problem?+
It means the numeric value of the character itself. The digit 2 must appear exactly 2 times. The digit 3 must appear exactly 3 times. It's a direct count-to-value match, nothing fancy. Hash Table counting makes this straightforward to check.
Is this really asked at J.P. Morgan and PornHub?+
Yes, it appears in reported assessments from both. It's easy-tier, so it often shows up as a warm-up or screening problem. Don't underestimate it just because difficulty is low; misreading the constraint costs time.
What about the digit 0? Does it need to appear 0 times?+
Yes. If the number contains a 0, the problem constraint is impossible to satisfy because 0 can't appear 0 times and also be part of the number. If 0 isn't in the string, that's fine. Hash Table will catch this when you validate.
Can I skip the Hash Table and just loop twice?+
You could, but Hash Table is cleaner and faster. One pass to count all digit frequencies, one pass to validate the rule. String and counting work, but Hash Table makes the logic obvious and reduces bugs under interview pressure.
How hard is this really compared to other Easy problems?+
70%+ acceptance rate means it's more about reading comprehension than algorithm difficulty. People fail because they misparse the constraint or overthink it. Once you understand the rule, it's a straightforward hash-count-and-validate pattern.
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