Can Convert String in K Moves
A medium-tier problem at 36% community acceptance, tagged with Hash Table, String. Reported in interviews at Infosys and 0 others.
Can Convert String in K Moves is a medium difficulty problem that trips up candidates who don't spot the character-frequency constraint. Infosys asks this. The catch: you're not just checking if a string transformation is possible, you're checking if it can happen within a bounded number of moves, where the cost of moving isn't what you'd expect. Most candidates start building a graph or greedy approach and hit a wall when they realize the problem isn't about path-finding. If this lands in your live OA and you blank on the trick, StealthCoder solves it in seconds, invisible to the proctor.
Companies that ask "Can Convert String in K Moves"
Can Convert String in K Moves is the kind of problem that decides whether you pass. StealthCoder reads the problem on screen and surfaces a working solution in under 2 seconds. Invisible to screen share. The proctor sees nothing. Built by a senior engineer who knows the OA is theater. This is the script.
Get StealthCoderThe real problem here is understanding what 'K moves' means in the context of string transformation. The naive instinct is to think about edit distance or BFS, but the actual constraint involves character frequency and a counter that increments per move. You need a Hash Table to track how many times each character needs to be replaced, then verify whether the total cost fits within K. The pattern isn't algorithmic complexity; it's recognizing that characters with high replacement frequency create a bottleneck. The cost formula is counterintuitive until you see it once. Common pitfall: trying to optimize the move order instead of just counting. This problem tests whether you read the problem statement twice and caught the real constraint. StealthCoder is your hedge if the wording confuses you in the live setting.
Pattern tags
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Make sure you actually pass it.
Can Convert String in K Moves recycles across companies for a reason. It's medium-tier, and most candidates blank under the timer. StealthCoder is the hedge: an AI overlay invisible during screen share. It reads the problem and surfaces a working solution in under 2 seconds. Built by a senior engineer who knows the OA is theater. This is the script. Works on HackerRank, CodeSignal, CoderPad, and Karat.
Can Convert String in K Moves interview FAQ
Is this problem actually about string matching or graph traversal?+
Neither. It's about counting character frequencies and validating a cost constraint. You need a Hash Table to track replacement counts, then check if the sum stays under K. The problem statement hides this; most candidates waste time on BFS or dynamic programming before realizing the pattern.
Why is the acceptance rate so low at 36%?+
The problem's wording obscures the actual constraint. Candidates misread what 'K moves' means and build the wrong algorithm. Once you see that it's a frequency-counting problem with a specific cost formula, the solution is straightforward. The barrier is reading comprehension, not complexity.
Does Infosys ask this problem often?+
It's on their reported problem list. Medium-difficulty string problems with hash table patterns are standard in online assessments. If you're prepping for Infosys, knowing how to translate problem constraints into frequency maps is core preparation.
What's the actual trick to solving this efficiently?+
The trick is recognizing the bottleneck: the character that requires the most moves to be replaced determines your total cost. Use a Hash Table to count character frequencies in both strings, then apply the cost formula. The algorithm itself is O(n) once you understand the constraint.
If I struggle with this in the real OA, how much time do I have to solve it?+
That depends on your specific assessment platform and time limits, which vary. Medium problems typically expect 20 to 30 minutes of focused work. If you hit a wall on the wording, stepping back to re-read the problem definition is faster than coding the wrong algorithm.
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